3/7y^2-21/3=0

Solution for 3/7y^2-21/3=0 equation:

3/7y^2-21/3=0


Domain of the equation: 7y^2!=0

y^2!=0/7

y^2!=√0

y!=0

y∈R


We add all the numbers together, and all the variables

3/7y^2-7=0

We multiply all the terms by the denominator


-7*7y^2+3=0

Wy multiply elements

-49y^2+3=0

a = -49; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-49)·3
Δ = 588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{588}=\sqrt{196*3}=\sqrt{196}*\sqrt{3}=14\sqrt{3}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{3}}{2*-49}=\frac{0-14\sqrt{3}}{-98}
=-\frac{14\sqrt{3}}{-98}
=-\frac{\sqrt{3}}{-7}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{3}}{2*-49}=\frac{0+14\sqrt{3}}{-98}
=\frac{14\sqrt{3}}{-98}
=\frac{\sqrt{3}}{-7}
$